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-105m=-49-14m^2
We move all terms to the left:
-105m-(-49-14m^2)=0
We get rid of parentheses
14m^2-105m+49=0
a = 14; b = -105; c = +49;
Δ = b2-4ac
Δ = -1052-4·14·49
Δ = 8281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8281}=91$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-105)-91}{2*14}=\frac{14}{28} =1/2 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-105)+91}{2*14}=\frac{196}{28} =7 $
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